M.Sc. Math and ICWAI
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350.00
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Class 9 - 10 | Mathematics, Physics, All Boards, All Medium | INR 350.00 /hour |
Class 11 - 12 | Mathematics, Statistics, All Boards, All Medium | INR 350.00 /hour |
College Level | Costing, Business Mathematics, English, Mathematics | INR 600.00 /hour |
Test Preparation | MAT, ACS, MPSC | INR 600.00 /hour |
(t^2, 2t) and (u^2, 2u) would be coordinates of A and B.
(t^2, 2t) and (u^2, 2u) would be coordinates of A and B.
They can meet when they all come to starting point for the first time. Hence LCM of 8, 15 and 12 would be
120.
In 2 hours all three can meet
They can meet when they all come to starting point for the first time. Hence LCM of 8, 15 and 12 would be
120.
In 2 hours all three can meet
Compound interest = P(1.12)^4- P =2850 (given)
i.e. P=4969.32
Simple interest = P(48)/100 = P(0.48)
=2385.27
Compound interest = P(1.12)^4- P =2850 (given)
i.e. P=4969.32
Simple interest = P(48)/100 = P(0.48)
=2385.27
Together work done per day = 1/20+1/18 = 38/360
In 5 days work completed = 5(38/360) = 19/36:
work left = 1-19/36 = 17/36
Together work done per day = 1/20+1/18 = 38/360
In 5 days work completed = 5(38/360) = 19/36:
work left = 1-19/36 = 17/36
Upstream = x-y=28/7 and downstream = x+y =56/7 where x = speed of boat and y = speed of current
Subtract to get -2y = -4 or y = 2km/hou
Upstream = x-y=28/7 and downstream = x+y =56/7 where x = speed of boat and y = speed of current
Subtract to get -2y = -4 or y = 2km/hou
20S = 18C
Loss = C-S = C-20C/18 = -C/9
Percentate= 1/9(100) = 11.01% of cost or
10% of selling price
20S = 18C
Loss = C-S = C-20C/18 = -C/9
Percentate= 1/9(100) = 11.01% of cost or
10% of selling price
Interest for 4 years = PNR/100 = 700/-.
Amount to be repaid = 2500+700 = 3200/-
Interest for 4 years = PNR/100 = 700/-.
Amount to be repaid = 2500+700 = 3200/-
Interest for 4 years = PNR/100 = 700/-.
Amount to be repaid = 2500+700 = 3200/-
Interest for 4 years = PNR/100 = 700/-.
Amount to be repaid = 2500+700 = 3200/-
20S = 18C
Loss = C-S = C-20C/18 = -C/9
Percentate= 1/9(100) = 11.01% of cost or
10% of selling price
20S = 18C
Loss = C-S = C-20C/18 = -C/9
Percentate= 1/9(100) = 11.01% of cost or
10% of selling price
20S = 18C
Loss = C-S = C-20C/18 = -C/9
Percentate= 1/9(100) = 11.01% of cost or
10% of selling price
20S = 18C
Loss = C-S = C-20C/18 = -C/9
Percentate= 1/9(100) = 11.01% of cost or
10% of selling price
Train length = distance = 130 m.
Relative speed = x-4 where x = speed of train.
(x-4) 8/3600 = 130/1000:
80x-320 = 130(36)
x = 62.5km/hr
Train length = distance = 130 m.
Relative speed = x-4 where x = speed of train.
(x-4) 8/3600 = 130/1000:
80x-320 = 130(36)
x = 62.5km/hr
Work done by both per day = 1/20+1/30 = 1/12
i.e. for 12 days wages = 3840/-
For one day wages = 3840/12 = 320/-(Ans)
Work done by both per day = 1/20+1/30 = 1/12
i.e. for 12 days wages = 3840/-
For one day wages = 3840/12 = 320/-(Ans)
Let R be the radius of small and r the big cirlce.
Then pi(R^2+r^2 ) = 97 and R+r= 13 :
i.e. pi{(13-r)^2+r^2)}=97
169+2r^2-26r = 30.89
No real roots and hence no solution
Let R be the radius of small and r the big cirlce.
Then pi(R^2+r^2 ) = 97 and R+r= 13 :
i.e. pi{(13-r)^2+r^2)}=97
169+2r^2-26r = 30.89
No real roots and hence no solution
Since tangent makes 90 degrees with Radius, we have a right angled triangle AOP:
AP^2 = 61^2-11^2 = 50x72
AP = 5x12 = 60 cm.
Perimeter of quadrilateral= 2(AP+OA) = 142 cm.
Since tangent makes 90 degrees with Radius, we have a right angled triangle AOP:
AP^2 = 61^2-11^2 = 50x72
AP = 5x12 = 60 cm.
Perimeter of quadrilateral= 2(AP+OA) = 142 cm.
Let the circle have equation x^2+y^2+2gx+2fy+c=0: The points on the circle are (0,.0)(a,0) and (0,b)
Hence c =0: a^2+2ga =0: and b^2+2fb =0:
a =-2g and b =-2f
Or equation is x^2+y^2-ax-by =0
Let the circle have equation x^2+y^2+2gx+2fy+c=0: The points on the circle are (0,.0)(a,0) and (0,b)
Hence c =0: a^2+2ga =0: and b^2+2fb =0:
a =-2g and b =-2f
Or equation is x^2+y^2-ax-by =0
Leaf:Wood = 3:2 = 12: 8 and Leaf:Forest = 4:5 = 12:15
Hence ratio of Leaf:Wood:Forest = 12:8:15
Leaf share =12(1400)/35 = 480
Leaf:Wood = 3:2 = 12: 8 and Leaf:Forest = 4:5 = 12:15
Hence ratio of Leaf:Wood:Forest = 12:8:15
Leaf share =12(1400)/35 = 480
There are 151 girls and 10 boys.
Hence ratio of boys:girls= 10:151
There are 151 girls and 10 boys.
Hence ratio of boys:girls= 10:151
r1+r2 = 13 and pi (r1^2+r2^2) = 97
Solving we get r1 = 4 and r2 =9
Area of smaller circle =16pi
r1+r2 = 13 and pi (r1^2+r2^2) = 97
Solving we get r1 = 4 and r2 =9
Area of smaller circle =16pi
If Seva takes less number of days, then Seva is more efficient.
Their effeciency ratio is = 1/16 :1/20
= 5:4
If Seva takes less number of days, then Seva is more efficient.
Their effeciency ratio is = 1/16 :1/20
= 5:4
Total of all 15 persons = 15(29)
Total of two persons = 2(55)
Hence total of 13 persons = 15(29)-2(55)=325
Average of 13 persons = 25 years
Total of all 15 persons = 15(29)
Total of two persons = 2(55)
Hence total of 13 persons = 15(29)-2(55)=325
Average of 13 persons = 25 years
Let the number be x. Then 0.82x-0.28x = 540:
x = 1000
28% of 1000 = 280 (answer)
Let the number be x. Then 0.82x-0.28x = 540:
x = 1000
28% of 1000 = 280 (answer)
Difference between Rita and Sushant as per ratio is 7-5 = 2
2 is equivalent to 4000 means
Total 15 is equivalent to 30000
Tuhin and Sushant total = 8(30000)/15 = 16000
Difference between Rita and Sushant as per ratio is 7-5 = 2
2 is equivalent to 4000 means
Total 15 is equivalent to 30000
Tuhin and Sushant total = 8(30000)/15 = 16000
Imagine a graph with origin at starting point. East 10 km, means he reached (10,0). Then left 6 km means he reaches (10, 6). When he turns left he walks in western direction and hence new poisition is (4,6). Last again turns left means goes towards south and reaches (4,0)
Distance from origin = 4 kms.
Imagine a graph with origin at starting point. East 10 km, means he reached (10,0). Then left 6 km means he reaches (10, 6). When he turns left he walks in western direction and hence new poisition is (4,6). Last again turns left means goes towards south and reaches (4...
At present average of old family members = 27+5 = 32
Total age = 32(5) = 160 years
New person added total = 160+x
Average = 36 = (160+x)/6
Hence x = new person age = 56
At present average of old family members = 27+5 = 32
Total age = 32(5) = 160 years
New person added total = 160+x
Average = 36 = (160+x)/6
Hence x = new person age = 56
60% are males and literate males = 60(20)% = 12% of 1000= 120
Total literate = 250 and females literate = 130
Percentage = 130/1000 (100) = 13%
60% are males and literate males = 60(20)% = 12% of 1000= 120
Total literate = 250 and females literate = 130
Percentage = 130/1000 (100) = 13%
At present girls = 5(720)/12 = 300 and boys = 420
To make them equal 120 girls must be admitted new.
At present girls = 5(720)/12 = 300 and boys = 420
To make them equal 120 girls must be admitted new.
CP 12 pens is equal to SP 15 pens. and 12 <15.
There will be a loss. So % loss is given by ( 15-12/15)*100= 20. So loss= 20%
CP 12 pens is equal to SP 15 pens. and 12 <15.
There will be a loss. So % loss is given by ( 15-12/15)*100= 20. So loss= 20%