B.Sc | St Stephens College, Delhi University | 2015 |
M.Sc | Annamalai University, Chennai | 2017 |
4 Years
I can explain the difficult concepts of mathematics in the easiest and simplest way. Dedicated to teaching and making a student's learning mathematics experience enjoyable. Student friendly nature.
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Covering of a to z syllabus in most easiest and interesting way with high level of quality. Student's understanding of a concept is the main target.
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Let length of the train be= x meter
speed of the train, (162+x)/18 = (120+x)/15,
Solving this equation, we get x=90 meter
Let length of the train be= x meter
speed of the train, (162+x)/18 = (120+x)/15,
Solving this equation, we get x=90 meter
20% water in 25kg mixture means 5kg water.
Let we add x letre of water to make it 33.33% or 1/3rd part.
(5+x)/(25+x) =1/3, solving for x, we get, x=5 letre
20% water in 25kg mixture means 5kg water.
Let we add x letre of water to make it 33.33% or 1/3rd part.
(5+x)/(25+x) =1/3, solving for x, we get, x=5 letre
Let CP=100
MP=130
SP= 130-20% discount=104
Gain=104-100=4 on 100 rupees
Gain%= 4%
Let CP=100
MP=130
SP= 130-20% discount=104
Gain=104-100=4 on 100 rupees
Gain%= 4%
2^m- 2^n = 56
2^n[2^(m-n) -1] =8*7
which gives, n=3, so m-n=3 gives m=6
so answer is 6,3
2^m- 2^n = 56
2^n[2^(m-n) -1] =8*7
which gives, n=3, so m-n=3 gives m=6
so answer is 6,3
slope at (1,1)= f'(1)=2+b
Equation of tangent line is, (y-1)=(2+b)(x-1)
put y=0 to get x-intercept=(1+b)/(2+b)
put x=0 to get y-intercept= -1-b
area, 1/2*(1+b)/(2+b)*(-1-b)=2, solving which we get b= -3
slope at (1,1)= f'(1)=2+b
Equation of tangent line is, (y-1)=(2+b)(x-1)
put y=0 to get x-intercept=(1+b)/(2+b)
put x=0 to get y-intercept= -1-b
area, 1/2*(1+b)/(2+b)*(-1-b)=2, solving which we get b= -3
Let the two consecutive odd numbers be x and x+2,
accoding to the question,
x(x+2) = 4(x+x+2)-1
x^2-6x-7 =0: x=7, -1
Larger number =9
Let the two consecutive odd numbers be x and x+2,
accoding to the question,
x(x+2) = 4(x+x+2)-1
x^2-6x-7 =0: x=7, -1
Larger number =9
uSING formula for
Product of roots=-b/a = -35/1=-35 and one of them is 5.
So the second root is -35/5= -7
uSING formula for
Product of roots=-b/a = -35/1=-35 and one of them is 5.
So the second root is -35/5= -7
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
You have not provided all the necessary details like the stream of your study and subjects in which you need tuition. Take some demo classes at some best institutes and decide accordingly.
I hope by CS you mean Civil Services. Its bit difficult but then YES you can do.
I hope by CS you mean Civil Services. Its bit difficult but then YES you can do.
Other options are XAT, MAT, GRE, GMAT etc.
Other options are XAT, MAT, GRE, GMAT etc.
TIME in Delhi is good coaching centre.
TIME in Delhi is good coaching centre.
Its a matter of personal interest.
Its a matter of personal interest.
Final Year Graduation.
Final Year Graduation.
Download the official notification and analyze it.
Download the official notification and analyze it.
Read, Write and Listen more in English.
Read, Write and Listen more in English.
Basically managing and controlling the things, events and persons is called management.
Basically managing and controlling the things, events and persons is called management.
2.. Structure is distorted trigonal bipyramidal
2.. Structure is distorted trigonal bipyramidal
Local minima is the minimum value of a function in neighbourhood of a given point. It is different from absolute minima.
First derivative test is used to obtain the critical points.
Local minima is the minimum value of a function in neighbourhood of a given point. It is different from absolute minima.
First derivative test is used to obtain the critical points.
n−type semiconductor conducts the electricity because of presence of extra electrons.
Hence, an element of group 14th can be converted to n−type semiconductor by doping it with the element of group 15 like P and As
n−type semiconductor conducts the electricity because of presence of extra electrons.
Hence, an element of group 14th can be converted to n−type semiconductor by doping it with the element of group 15 like P and As
When we add a cation of higher valence impurity in an ionic solid, two or more than two cations of lower valances iare replace by less than 2 ions of higher valances . To maintain the electrical neutrality few sites become vacant,
For example,
Sr2+ is added to NaCl, each Sr2+ ion replaces two Na+ ions. Because the charge on 1 ions of Sr2+ is equal to charge on two ions of Na+. and One Na+ ions leave there
When we add a cation of higher valence impurity in an ionic solid, two or more than two cations of lower valances iare replace by less than 2 ions of higher valances . To maintain the electrical neutrality few sites become vacant,
For example,
...R in roster form is
R= {(5,4)}
only one element will be there.
R in roster form is
R= {(5,4)}
only one element will be there.
vacancy defect can arise.
A solid crystal is said to have vacancy defect if some of the lattice sites are vacant.
Vacancy defect results to a decrease in the density of the solid.
vacancy defect can arise.
A solid crystal is said to have vacancy defect if some of the lattice sites are vacant.
Vacancy defect results to a decrease in the density of the solid.
Potassium sulphate Ionic solid
Benzene Molecular solid (non−polar)
Urea Polar molecular solid
Ammonia Polar molecular solid
Water Hydrogen bonded molecular solid
Zinc sulphide Ionic solid
Graphite Covalent or network solid
Rubidium Metallic solid
Argon Non−polar molecular solid
Silicon carbide Covalent or network solid
Potassium sulphate Ionic solid
Benzene Molecular solid (non−polar)
Urea Polar molecular solid
Ammonia Polar molecular solid
Water Hydrogen bonded molecular solid
...It is a direct ncert question.
It will be an Isotropic solid which has same value of reflective index in all the direction. All isotropic solid are amorphous solid.Amorphous solid cuts into two pieces with irregular surfaces.
It is a direct ncert question.
It will be an Isotropic solid which has same value of reflective index in all the direction. All isotropic solid are amorphous solid.Amorphous solid cuts into two pieces with irregular surfaces.
Assume the x-axis to be a mirror.
take the image of (3,5) in x-axis which is (3,-5) .
Use the following concept to reach to the final answer.
as we know that reflected ray when extended back passes through the image of a point on incident ray i.e reflected ray passes through.
Assume the x-axis to be a mirror.
take the image of (3,5) in x-axis which is (3,-5) .
Use the following concept to reach to the final answer.
as we know that reflected ray when extended back passes through the image of a point on incident ray i.e refl...
tan 30= h/a
tan 60= h/b
multiplying both, we get
tan30*tan60 =h*h/ab
h=root(ab)
tan 30= h/a
tan 60= h/b
multiplying both, we get
tan30*tan60 =h*h/ab
h=root(ab)
If angles x and y are complimentary, then there is pretty simple formula to calculate
the hieght OP as follow-
OP= Square root of (OQ*OR)
If angles x and y are complimentary, then there is pretty simple formula to calculate
the hieght OP as follow-
OP= Square root of (OQ*OR)
Work = dot product of Force and Distance,
it is a scalar, hence dimensionless.
Work = dot product of Force and Distance,
it is a scalar, hence dimensionless.
Magnetic field strength -
It is one of two ways that the intensity of a magnetic field can be measured.
Its unit is Newton-meters per ampere (Nm/A), also called teslas (T).
Magnetic field strength -
It is one of two ways that the intensity of a magnetic field can be measured.
Its unit is Newton-meters per ampere (Nm/A), also called teslas (T).
Probability of an event= Number of favorable outcomes/Total number of outcomes
P(an ace) = 4/52 = 1/13
P(not a red card) = 1- P(Red card) =1-26/52 = 1-1/2=1/2
Probability of an event= Number of favorable outcomes/Total number of outcomes
P(an ace) = 4/52 = 1/13
P(not a red card) = 1- P(Red card) =1-26/52 = 1-1/2=1/2
These days SI system is used worldwide, earlier Foot, Pound and Second (FPS) System was very common.
These days SI system is used worldwide, earlier Foot, Pound and Second (FPS) System was very common.
Since two trains are moving in opposite directions, velocities get added.
Relative velocity of B w.r.t A = (90+54) = 144 km/hr
= 144*5/18 m/s = 40 m/s
Option D
Since two trains are moving in opposite directions, velocities get added.
Relative velocity of B w.r.t A = (90+54) = 144 km/hr
= 144*5/18 m/s = 40 m/s
Option D
There are 6 Blue and 5 Green pens.
Total pens=18
P (neither green nor blue) = P (yellow) =7/18
P (not blue)= 1- P (blue)=1-6/18 = 2/3
There are 6 Blue and 5 Green pens.
Total pens=18
P (neither green nor blue) = P (yellow) =7/18
P (not blue)= 1- P (blue)=1-6/18 = 2/3
Ans-A
Reason- In a free fall motion, acceleration is Earth's gravity which always points downward and Its value is constant. Obviously velocity becomes zero when body reaches its higest point.
Ans-A
Reason- In a free fall motion, acceleration is Earth's gravity which always points downward and Its value is constant. Obviously velocity becomes zero when body reaches its higest point.
Ans- C
Impending motion-
It refers to the state just before surfaces start to slip. In this case the static frictional force reaches its upper limit.
Ans- C
Impending motion-
It refers to the state just before surfaces start to slip. In this case the static frictional force reaches its upper limit.
Answer-B
Reason- because the two curves coincide means overlap, two objects will have same velocity at given point of time. Remember the slop of velocity-time graph represents the acceleration of the body!
Answer-B
Reason- because the two curves coincide means overlap, two objects will have same velocity at given point of time. Remember the slop of velocity-time graph represents the acceleration of the body!
Ans-B
Acceleration at any point of the time is the slope of the velocity-time graph because acceleration is defined as the rate of change of velocity wrt to time.
Ans-B
Acceleration at any point of the time is the slope of the velocity-time graph because acceleration is defined as the rate of change of velocity wrt to time.
Normal to the surface= Weight*coeff of friction =Mg*(mu)=40*0.1 N= 4N in opposite direction
Net force= 20-4=16N
Acceleration= Force/Normal reaction= 16/4= 4m/s*s
Normal to the surface= Weight*coeff of friction =Mg*(mu)=40*0.1 N= 4N in opposite direction
Net force= 20-4=16N
Acceleration= Force/Normal reaction= 16/4= 4m/s*s
Ans-D
centrepetal acc= v2 / r
=6*6/0.3= 120m/s*s
Ans-D
centrepetal acc= v2 / r
=6*6/0.3= 120m/s*s
ans- D
centrepetal acc=v2 / r
r= 6*6/120=.3m=30cm
ans- D
centrepetal acc=v2 / r
r= 6*6/120=.3m=30cm
Force of friction= Normal reaction*(coeff of friction)
=1*10*0.2=2N
So, ans is B
Force of friction= Normal reaction*(coeff of friction)
=1*10*0.2=2N
So, ans is B